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10013001203 = 53188924551
BaseRepresentation
bin10010101001101001…
…00100010111110011
3221211211020011102102
421110310210113303
5131001312014303
64333325211015
7503063051222
oct112464442763
927754204372
1010013001203
114279095007
121b35400a6b
13c375c00aa
146adb88cb9
153d90ca288
hex254d245f3

10013001203 has 4 divisors (see below), whose sum is σ = 10201925808. Its totient is φ = 9824076600.

The previous prime is 10013001169. The next prime is 10013001223. The reversal of 10013001203 is 30210031001.

10013001203 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 10013001203 - 28 = 10013000947 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (10013001223) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 94462223 + ... + 94462328.

It is an arithmetic number, because the mean of its divisors is an integer number (2550481452).

Almost surely, 210013001203 is an apocalyptic number.

10013001203 is a deficient number, since it is larger than the sum of its proper divisors (188924605).

10013001203 is an equidigital number, since it uses as much as digits as its factorization.

10013001203 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 188924604.

The product of its (nonzero) digits is 18, while the sum is 11.

Adding to 10013001203 its reverse (30210031001), we get a palindrome (40223032204).

The spelling of 10013001203 in words is "ten billion, thirteen million, one thousand, two hundred three".

Divisors: 1 53 188924551 10013001203