100130244431 has 4 divisors (see below), whose sum is σ = 114434565072. Its totient is φ = 85825923792.

The previous prime is 100130244391. The next prime is 100130244499. The reversal of 100130244431 is 134442031001.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 134442031001 = 172127 ⋅781063.

It is not a de Polignac number, because 100130244431 - 2¹⁸ = 100129982287 is a prime.

It is a super-2 number, since 2×100130244431² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 100130244397 and 100130244406.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (100130243431) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7152160310 + ... + 7152160323.

It is an arithmetic number, because the mean of its divisors is an integer number (28608641268).

Almost surely, 2^100130244431 is an apocalyptic number.

100130244431 is a deficient number, since it is larger than the sum of its proper divisors (14304320641).

100130244431 is an equidigital number, since it uses as much as digits as its factorization.

100130244431 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 14304320640.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 100130244431 its reverse (134442031001), we get a palindrome (234572275432).

The spelling of 100130244431 in words is "one hundred billion, one hundred thirty million, two hundred forty-four thousand, four hundred thirty-one".