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10013062141 = 45832184827
BaseRepresentation
bin10010101001101001…
…10011001111111101
3221211211100021000101
421110310303033331
5131001320442031
64333330401101
7503063423665
oct112464631775
927754307011
1010013062141
114279126875
121b35430191
13c37611a54
146adba31a5
153d90dd361
hex254d333fd

10013062141 has 4 divisors (see below), whose sum is σ = 10015251552. Its totient is φ = 10010872732.

The previous prime is 10013062061. The next prime is 10013062151. The reversal of 10013062141 is 14126031001.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 10013062141 - 211 = 10013060093 is a prime.

It is a super-2 number, since 2×100130621412 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10013062151) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1087831 + ... + 1096996.

It is an arithmetic number, because the mean of its divisors is an integer number (2503812888).

Almost surely, 210013062141 is an apocalyptic number.

It is an amenable number.

10013062141 is a deficient number, since it is larger than the sum of its proper divisors (2189411).

10013062141 is an equidigital number, since it uses as much as digits as its factorization.

10013062141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2189410.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 10013062141 its reverse (14126031001), we get a palindrome (24139093142).

The spelling of 10013062141 in words is "ten billion, thirteen million, sixty-two thousand, one hundred forty-one".

Divisors: 1 4583 2184827 10013062141