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10013102032103 = 41652393743497
BaseRepresentation
bin1001000110110101101101…
…1000111100010011100111
31022110020120022000110000122
42101231123120330103213
52303023313110011403
633143542223032155
72052265000646522
oct221553330742347
938406508013018
1010013102032103
113210595068725
12115873373b65b
13578301702941
142688cb257bb9
151256e52eb838
hex91b5b63c4e7

10013102032103 has 8 divisors (see below), whose sum is σ = 10257483999840. Its totient is φ = 9768727681920.

The previous prime is 10013102032099. The next prime is 10013102032111. The reversal of 10013102032103 is 30123020131001.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 10013102032103 - 22 = 10013102032099 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10013102038103) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 803051 + ... + 4546547.

It is an arithmetic number, because the mean of its divisors is an integer number (1282185499980).

Almost surely, 210013102032103 is an apocalyptic number.

10013102032103 is a deficient number, since it is larger than the sum of its proper divisors (244381967737).

10013102032103 is an equidigital number, since it uses as much as digits as its factorization.

10013102032103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3808777.

The product of its (nonzero) digits is 108, while the sum is 17.

Adding to 10013102032103 its reverse (30123020131001), we get a palindrome (40136122163104).

The spelling of 10013102032103 in words is "ten trillion, thirteen billion, one hundred two million, thirty-two thousand, one hundred three".

Divisors: 1 41 65239 2674799 3743497 153483377 244222000783 10013102032103