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100131132311 = 714304447473
BaseRepresentation
bin101110101000001000…
…1111101001110010111
3100120110022101112221222
41131100101331032113
53120032032213221
6113555525400555
710143225403310
oct1352021751627
9316408345858
10100131132311
1139513460811
12174a586915b
139599a33722
144bbc637607
1529109dd9ab
hex175047d397

100131132311 has 4 divisors (see below), whose sum is σ = 114435579792. Its totient is φ = 85826684832.

The previous prime is 100131132287. The next prime is 100131132313. The reversal of 100131132311 is 113231131001.

It is a semiprime because it is the product of two primes.

It is a de Polignac number, because none of the positive numbers 2k-100131132311 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 100131132311.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (100131132313) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7152223730 + ... + 7152223743.

It is an arithmetic number, because the mean of its divisors is an integer number (28608894948).

Almost surely, 2100131132311 is an apocalyptic number.

100131132311 is a deficient number, since it is larger than the sum of its proper divisors (14304447481).

100131132311 is an equidigital number, since it uses as much as digits as its factorization.

100131132311 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 14304447480.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 100131132311 its reverse (113231131001), we get a palindrome (213362263312).

The spelling of 100131132311 in words is "one hundred billion, one hundred thirty-one million, one hundred thirty-two thousand, three hundred eleven".

Divisors: 1 7 14304447473 100131132311