100131135222361 has 4 divisors (see below), whose sum is σ = 100241533387792. Its totient is φ = 100020737056932.

The previous prime is 100131135222359. The next prime is 100131135222367. The reversal of 100131135222361 is 163222531131001.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 100131135222361 - 2¹ = 100131135222359 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (100131135222367) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 55199081355 + ... + 55199083168.

It is an arithmetic number, because the mean of its divisors is an integer number (25060383346948).

Almost surely, 2^{100131135222361} is an apocalyptic number.

It is an amenable number.

100131135222361 is a deficient number, since it is larger than the sum of its proper divisors (110398165431).

100131135222361 is an equidigital number, since it uses as much as digits as its factorization.

100131135222361 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 110398165430.

The product of its (nonzero) digits is 6480, while the sum is 31.

Adding to 100131135222361 its reverse (163222531131001), we get a palindrome (263353666353362).

The spelling of 100131135222361 in words is "one hundred trillion, one hundred thirty-one billion, one hundred thirty-five million, two hundred twenty-two thousand, three hundred sixty-one".