Search a number
-
+
1001313102301 = 2116347314327
BaseRepresentation
bin11101001001000101110…
…10010110100111011101
310112201120020020221012121
432210202322112213131
5112401142123233201
62043555154502541
7132225320636431
oct16444272264735
93481506227177
101001313102301
11356722162106
12142089894a51
1373567340455
143666c9b89c1
151b0a6b939a1
hexe922e969dd

1001313102301 has 4 divisors (see below), whose sum is σ = 1001360437792. Its totient is φ = 1001265766812.

The previous prime is 1001313102281. The next prime is 1001313102329. The reversal of 1001313102301 is 1032013131001.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1001313102301 - 217 = 1001312971229 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1001313102401) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23636001 + ... + 23678326.

It is an arithmetic number, because the mean of its divisors is an integer number (250340109448).

Almost surely, 21001313102301 is an apocalyptic number.

It is an amenable number.

1001313102301 is a deficient number, since it is larger than the sum of its proper divisors (47335491).

1001313102301 is an equidigital number, since it uses as much as digits as its factorization.

1001313102301 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 47335490.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 1001313102301 its reverse (1032013131001), we get a palindrome (2033326233302).

The spelling of 1001313102301 in words is "one trillion, one billion, three hundred thirteen million, one hundred two thousand, three hundred one".

Divisors: 1 21163 47314327 1001313102301