100132201112001 has 4 divisors (see below), whose sum is σ = 133509601482672. Its totient is φ = 66754800741332.

The previous prime is 100132201111967. The next prime is 100132201112093. The reversal of 100132201112001 is 100211102231001.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 100132201112001 - 2¹¹ = 100132201109953 is a prime.

It is a super-3 number, since 3×100132201112001³ (a number of 43 digits) contains 333 as substring.

It is not an unprimeable number, because it can be changed into a prime (100132201112401) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16688700185331 + ... + 16688700185336.

It is an arithmetic number, because the mean of its divisors is an integer number (33377400370668).

Almost surely, 2^{100132201112001} is an apocalyptic number.

It is an amenable number.

100132201112001 is a deficient number, since it is larger than the sum of its proper divisors (33377400370671).

100132201112001 is an equidigital number, since it uses as much as digits as its factorization.

100132201112001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 33377400370670.

The product of its (nonzero) digits is 24, while the sum is 15.

Adding to 100132201112001 its reverse (100211102231001), we get a palindrome (200343303343002).

The spelling of 100132201112001 in words is "one hundred trillion, one hundred thirty-two billion, two hundred one million, one hundred twelve thousand, one".