100133000322221 has 4 divisors (see below), whose sum is σ = 100133286231132. Its totient is φ = 100132714413312.

The previous prime is 100133000322211. The next prime is 100133000322239. The reversal of 100133000322221 is 122223000331001.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 75119298445321 + 25013701876900 = 8667139^2 + 5001370^2 .

It is a cyclic number.

It is not a de Polignac number, because 100133000322221 - 2¹⁴ = 100133000305837 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 100133000322193 and 100133000322202.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (100133000322211) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 142428470 + ... + 143129783.

It is an arithmetic number, because the mean of its divisors is an integer number (25033321557783).

Almost surely, 2^{100133000322221} is an apocalyptic number.

It is an amenable number.

100133000322221 is a deficient number, since it is larger than the sum of its proper divisors (285908911).

100133000322221 is an equidigital number, since it uses as much as digits as its factorization.

100133000322221 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 285908910.

The product of its (nonzero) digits is 432, while the sum is 20.

Adding to 100133000322221 its reverse (122223000331001), we get a palindrome (222356000653222).

The spelling of 100133000322221 in words is "one hundred trillion, one hundred thirty-three billion, three hundred twenty-two thousand, two hundred twenty-one".