1001330211133 has 4 divisors (see below), whose sum is σ = 1144377384160. Its totient is φ = 858283038108.

The previous prime is 1001330211107. The next prime is 1001330211137. The reversal of 1001330211133 is 3311120331001.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1001330211133 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1001330211133.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1001330211137) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 71523586503 + ... + 71523586516.

It is an arithmetic number, because the mean of its divisors is an integer number (286094346040).

Almost surely, 2^{1001330211133} is an apocalyptic number.

It is an amenable number.

1001330211133 is a deficient number, since it is larger than the sum of its proper divisors (143047173027).

1001330211133 is an equidigital number, since it uses as much as digits as its factorization.

1001330211133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 143047173026.

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 1001330211133 its reverse (3311120331001), we get a palindrome (4312450542134).

The spelling of 1001330211133 in words is "one trillion, one billion, three hundred thirty million, two hundred eleven thousand, one hundred thirty-three".