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10013312121 = 33337770707
BaseRepresentation
bin10010101001101011…
…10000010001111001
3221211211210221220220
421110311300101321
5131001401441441
64333340010253
7503065514541
oct112465602171
927754727826
1010013312121
11427928766a
121b35530989
13c3769b777
146adc2a321
153d913c466
hex254d70479

10013312121 has 4 divisors (see below), whose sum is σ = 13351082832. Its totient is φ = 6675541412.

The previous prime is 10013312119. The next prime is 10013312129. The reversal of 10013312121 is 12121331001.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 10013312121 - 21 = 10013312119 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 10013312121.

It is not an unprimeable number, because it can be changed into a prime (10013312129) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1668885351 + ... + 1668885356.

It is an arithmetic number, because the mean of its divisors is an integer number (3337770708).

Almost surely, 210013312121 is an apocalyptic number.

It is an amenable number.

10013312121 is a deficient number, since it is larger than the sum of its proper divisors (3337770711).

10013312121 is an equidigital number, since it uses as much as digits as its factorization.

10013312121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3337770710.

The product of its (nonzero) digits is 36, while the sum is 15.

Adding to 10013312121 its reverse (12121331001), we get a palindrome (22134643122).

The spelling of 10013312121 in words is "ten billion, thirteen million, three hundred twelve thousand, one hundred twenty-one".

Divisors: 1 3 3337770707 10013312121