100133122021 has 4 divisors (see below), whose sum is σ = 100134133792. Its totient is φ = 100132110252.

The previous prime is 100133122013. The next prime is 100133122039. The reversal of 100133122021 is 120221331001.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 100133122021 - 2³ = 100133122013 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 100133121986 and 100133122004.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (100133123021) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 339105 + ... + 561478.

It is an arithmetic number, because the mean of its divisors is an integer number (25033533448).

Almost surely, 2^100133122021 is an apocalyptic number.

It is an amenable number.

100133122021 is a deficient number, since it is larger than the sum of its proper divisors (1011771).

100133122021 is an equidigital number, since it uses as much as digits as its factorization.

100133122021 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1011770.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 100133122021 its reverse (120221331001), we get a palindrome (220354453022).

The spelling of 100133122021 in words is "one hundred billion, one hundred thirty-three million, one hundred twenty-two thousand, twenty-one".