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1001332025 = 52231741447
BaseRepresentation
bin111011101011110…
…001110100111001
32120210011221022022
4323223301310321
54022320111100
6243210004225
733546116231
oct7353616471
92523157268
101001332025
11474253631
1223b416675
1312c5b5575
1496db6cc1
155cd95e85
hex3baf1d39

1001332025 has 12 divisors (see below), whose sum is σ = 1295637312. Its totient is φ = 766236240.

The previous prime is 1001331997. The next prime is 1001332049. The reversal of 1001332025 is 5202331001.

It is not a de Polignac number, because 1001332025 - 214 = 1001315641 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 1001331994 and 1001332012.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 870149 + ... + 871298.

It is an arithmetic number, because the mean of its divisors is an integer number (107969776).

Almost surely, 21001332025 is an apocalyptic number.

It is an amenable number.

1001332025 is a deficient number, since it is larger than the sum of its proper divisors (294305287).

1001332025 is a wasteful number, since it uses less digits than its factorization.

1001332025 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1741480 (or 1741475 counting only the distinct ones).

The product of its (nonzero) digits is 180, while the sum is 17.

The square root of 1001332025 is about 31643.8307573530. The cubic root of 1001332025 is about 1000.4438113357.

Adding to 1001332025 its reverse (5202331001), we get a palindrome (6203663026).

The spelling of 1001332025 in words is "one billion, one million, three hundred thirty-two thousand, twenty-five".

Divisors: 1 5 23 25 115 575 1741447 8707235 40053281 43536175 200266405 1001332025