10013350113 has 64 divisors (see below), whose sum is σ = 16858195200. Its totient is φ = 5823290880.

The previous prime is 10013350111. The next prime is 10013350121. The reversal of 10013350113 is 31105331001.

10013350113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is not a de Polignac number, because 10013350113 - 2¹ = 10013350111 is a prime.

It is a super-2 number, since 2×10013350113² (a number of 21 digits) contains 22 as substring.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (10013350111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 3072781 + ... + 3076037.

It is an arithmetic number, because the mean of its divisors is an integer number (263409300).

Almost surely, 2^10013350113 is an apocalyptic number.

10013350113 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

10013350113 is a deficient number, since it is larger than the sum of its proper divisors (6844845087).

10013350113 is a wasteful number, since it uses less digits than its factorization.

10013350113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3759 (or 3753 counting only the distinct ones).

The product of its (nonzero) digits is 135, while the sum is 18.

Adding to 10013350113 its reverse (31105331001), we get a palindrome (41118681114).

The spelling of 10013350113 in words is "ten billion, thirteen million, three hundred fifty thousand, one hundred thirteen".