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1001340114 = 23315383549
BaseRepresentation
bin111011101011110…
…011110011010010
32120210012100101220
4323223303303102
54022320340424
6243210105510
733546151635
oct7353636322
92523170356
101001340114
11474259715
1223b41b296
1312c5b9158
1496db9c1c
155cd98579
hex3baf3cd2

1001340114 has 16 divisors (see below), whose sum is σ = 2067283200. Its totient is φ = 323012880.

The previous prime is 1001340113. The next prime is 1001340127. The reversal of 1001340114 is 4110431001.

It is a junction number, because it is equal to n+sod(n) for n = 1001340093 and 1001340102.

It is not an unprimeable number, because it can be changed into a prime (1001340113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2691589 + ... + 2691960.

It is an arithmetic number, because the mean of its divisors is an integer number (129205200).

Almost surely, 21001340114 is an apocalyptic number.

1001340114 is an abundant number, since it is smaller than the sum of its proper divisors (1065943086).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1001340114 is a wasteful number, since it uses less digits than its factorization.

1001340114 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5383585.

The product of its (nonzero) digits is 48, while the sum is 15.

The square root of 1001340114 is about 31643.9585703180. The cubic root of 1001340114 is about 1000.4465052700.

Adding to 1001340114 its reverse (4110431001), we get a palindrome (5111771115).

The spelling of 1001340114 in words is "one billion, one million, three hundred forty thousand, one hundred fourteen".

Divisors: 1 2 3 6 31 62 93 186 5383549 10767098 16150647 32301294 166890019 333780038 500670057 1001340114