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10014002241 = 33338000747
BaseRepresentation
bin10010101001110000…
…11000110001000001
3221211220010000120220
421110320120301001
5131002041032431
64333402453253
7503104420545
oct112470306101
927756100526
1010014002241
114279709111
121b35804229
13c37880919
146add69a25
153d9226b96
hex254e18c41

10014002241 has 4 divisors (see below), whose sum is σ = 13352002992. Its totient is φ = 6676001492.

The previous prime is 10014002227. The next prime is 10014002263. The reversal of 10014002241 is 14220041001.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 10014002241 - 29 = 10014001729 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 10014002241.

It is not an unprimeable number, because it can be changed into a prime (10014002291) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1669000371 + ... + 1669000376.

It is an arithmetic number, because the mean of its divisors is an integer number (3338000748).

Almost surely, 210014002241 is an apocalyptic number.

It is an amenable number.

10014002241 is a deficient number, since it is larger than the sum of its proper divisors (3338000751).

10014002241 is an equidigital number, since it uses as much as digits as its factorization.

10014002241 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3338000750.

The product of its (nonzero) digits is 64, while the sum is 15.

Adding to 10014002241 its reverse (14220041001), we get a palindrome (24234043242).

The spelling of 10014002241 in words is "ten billion, fourteen million, two thousand, two hundred forty-one".

Divisors: 1 3 3338000747 10014002241