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10014343851 = 319175690243
BaseRepresentation
bin10010101001110011…
…01100001010101011
3221211220202101012010
421110321230022223
5131002133000401
64333414051003
7503110342521
oct112471541253
927756671163
1010014343851
114279921836
121b35949a63
13c37970265
146b0018311
153d9292ed6
hex254e6c2ab

10014343851 has 8 divisors (see below), whose sum is σ = 14055219520. Its totient is φ = 6324848712.

The previous prime is 10014343847. The next prime is 10014343853. The reversal of 10014343851 is 15834341001.

10014343851 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 10014343851 - 22 = 10014343847 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (10014343853) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 87845065 + ... + 87845178.

It is an arithmetic number, because the mean of its divisors is an integer number (1756902440).

Almost surely, 210014343851 is an apocalyptic number.

10014343851 is a deficient number, since it is larger than the sum of its proper divisors (4040875669).

10014343851 is a wasteful number, since it uses less digits than its factorization.

10014343851 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 175690265.

The product of its (nonzero) digits is 5760, while the sum is 30.

Adding to 10014343851 its reverse (15834341001), we get a palindrome (25848684852).

The spelling of 10014343851 in words is "ten billion, fourteen million, three hundred forty-three thousand, eight hundred fifty-one".

Divisors: 1 3 19 57 175690243 527070729 3338114617 10014343851