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10017234125553 = 317260719034437
BaseRepresentation
bin1001000111000101000110…
…1011101000001011110001
31022110122020021021112121210
42101301101223220023301
52303110243414004203
633145504232110333
72052502254113304
oct221612153501361
938418207245553
1010017234125553
113212315573696
1211594a75353a9
1357880c7c3955
14268b9dd54b3b
15125887e65803
hex91c51ae82f1

10017234125553 has 24 divisors (see below), whose sum is σ = 14211568237312. Its totient is φ = 6274968309504.

The previous prime is 10017234125537. The next prime is 10017234125581. The reversal of 10017234125553 is 35552143271001.

It is not a de Polignac number, because 10017234125553 - 24 = 10017234125537 is a prime.

It is a super-2 number, since 2×100172341255532 (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (10017234135553) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 8990950 + ... + 10043487.

Almost surely, 210017234125553 is an apocalyptic number.

It is an amenable number.

10017234125553 is a deficient number, since it is larger than the sum of its proper divisors (4194334111759).

10017234125553 is a wasteful number, since it uses less digits than its factorization.

10017234125553 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 19035081 (or 19035064 counting only the distinct ones).

The product of its (nonzero) digits is 126000, while the sum is 39.

Adding to 10017234125553 its reverse (35552143271001), we get a palindrome (45569377396554).

The spelling of 10017234125553 in words is "ten trillion, seventeen billion, two hundred thirty-four million, one hundred twenty-five thousand, five hundred fifty-three".

Divisors: 1 3 17 51 289 607 867 1821 10319 30957 175423 526269 19034437 57103311 323585429 970756287 5500952293 11553903259 16502856879 34661709777 196416355403 589249066209 3339078041851 10017234125553