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1002002112113 = 6147934292827
BaseRepresentation
bin11101001010010111111…
…10101101111001110001
310112210100020202020222112
432211023332231321301
5112404100020041423
62044151410415105
7132251355265412
oct16451376557161
93483306666875
101002002112113
11356a46085402
12142240591495
1373647002372
14366d62d1809
151b0e73e4a78
hexe94bfade71

1002002112113 has 8 divisors (see below), whose sum is σ = 1020554561280. Its totient is φ = 983518249680.

The previous prime is 1002002112109. The next prime is 1002002112119. The reversal of 1002002112113 is 3112112002001.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1002002112113 - 22 = 1002002112109 is a prime.

It is a super-3 number, since 3×10020021121133 (a number of 37 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1002002112119) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 17117195 + ... + 17175632.

It is an arithmetic number, because the mean of its divisors is an integer number (127569320160).

Almost surely, 21002002112113 is an apocalyptic number.

It is an amenable number.

1002002112113 is a deficient number, since it is larger than the sum of its proper divisors (18552449167).

1002002112113 is an equidigital number, since it uses as much as digits as its factorization.

1002002112113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 34293367.

The product of its (nonzero) digits is 24, while the sum is 14.

Adding to 1002002112113 its reverse (3112112002001), we get a palindrome (4114114114114).

The spelling of 1002002112113 in words is "one trillion, two billion, two million, one hundred twelve thousand, one hundred thirteen".

Divisors: 1 61 479 29219 34292827 2091862447 16426264133 1002002112113