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100201003413 = 372681639479
BaseRepresentation
bin101110101010001110…
…0011111100110010101
3100120122011212101002120
41131110130133212111
53120202424102123
6114010503130153
710145034322200
oct1352434374625
9316564771076
10100201003413
1139549943a25
1217505143959
1395ab358684
144bc7a24937
152916be12e3
hex175471f995

100201003413 has 12 divisors (see below), whose sum is σ = 155413801440. Its totient is φ = 57257716152.

The previous prime is 100201003363. The next prime is 100201003429. The reversal of 100201003413 is 314300102001.

It is not a de Polignac number, because 100201003413 - 213 = 100200995221 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 100201003392 and 100201003401.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (100201003213) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 340819593 + ... + 340819886.

It is an arithmetic number, because the mean of its divisors is an integer number (12951150120).

Almost surely, 2100201003413 is an apocalyptic number.

It is an amenable number.

100201003413 is a deficient number, since it is larger than the sum of its proper divisors (55212798027).

100201003413 is an equidigital number, since it uses as much as digits as its factorization.

100201003413 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 681639496 (or 681639489 counting only the distinct ones).

The product of its (nonzero) digits is 72, while the sum is 15.

Adding to 100201003413 its reverse (314300102001), we get a palindrome (414501105414).

The spelling of 100201003413 in words is "one hundred billion, two hundred one million, three thousand, four hundred thirteen".

Divisors: 1 3 7 21 49 147 681639479 2044918437 4771476353 14314429059 33400334471 100201003413