Base | Representation |
---|---|
bin | 101110101010010000… |
… | …0010101100110000101 |
3 | 100120122020202120021002 |
4 | 1131110200111212011 |
5 | 3120203203323023 |
6 | 114010540503045 |
7 | 10145046016616 |
oct | 1352440254605 |
9 | 316566676232 |
10 | 100202011013 |
11 | 3954a471a55 |
12 | 1750554aa85 |
13 | 95ab61c1a0 |
14 | 4bc7c07c0d |
15 | 2916d3eb28 |
hex | 1754815985 |
100202011013 has 8 divisors (see below), whose sum is σ = 107920987608. Its totient is φ = 92484624384.
The previous prime is 100202010973. The next prime is 100202011033. The reversal of 100202011013 is 310110202001.
It can be written as a sum of positive squares in 4 ways, for example, as 36519974404 + 63682036609 = 191102^2 + 252353^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 100202011013 - 210 = 100202009989 is a prime.
It is a super-2 number, since 2×1002020110132 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 100202010985 and 100202011003.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (100202011033) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 264956 + ... + 520197.
It is an arithmetic number, because the mean of its divisors is an integer number (13490123451).
Almost surely, 2100202011013 is an apocalyptic number.
100202011013 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
100202011013 is a deficient number, since it is larger than the sum of its proper divisors (7718976595).
100202011013 is an equidigital number, since it uses as much as digits as its factorization.
100202011013 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 794983.
The product of its (nonzero) digits is 12, while the sum is 11.
Adding to 100202011013 its reverse (310110202001), we get a palindrome (410312213014).
The spelling of 100202011013 in words is "one hundred billion, two hundred two million, eleven thousand, thirteen".
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