Base | Representation |
---|---|
bin | 11101001010011010000… |
… | …11011101010010110011 |
3 | 10112210101111122202122110 |
4 | 32211031003131102303 |
5 | 112404114123211034 |
6 | 2044153252540403 |
7 | 132251664406524 |
oct | 16451503352263 |
9 | 3483344582573 |
10 | 1002020132019 |
11 | 356a55272a95 |
12 | 142246621703 |
13 | 7364a97142a |
14 | 366d886284b |
15 | 1b0e8ca3de9 |
hex | e94d0dd4b3 |
1002020132019 has 16 divisors (see below), whose sum is σ = 1444714887168. Its totient is φ = 615341523072.
The previous prime is 1002020131997. The next prime is 1002020132051. The reversal of 1002020132019 is 9102310202001.
It is not a de Polignac number, because 1002020132019 - 239 = 452264318131 is a prime.
It is a super-4 number, since 4×10020201320194 (a number of 49 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.
It is a junction number, because it is equal to n+sod(n) for n = 1002020131986 and 1002020132004.
It is not an unprimeable number, because it can be changed into a prime (1002020132059) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 209013067 + ... + 209017860.
It is an arithmetic number, because the mean of its divisors is an integer number (90294680448).
Almost surely, 21002020132019 is an apocalyptic number.
1002020132019 is a deficient number, since it is larger than the sum of its proper divisors (442694755149).
1002020132019 is a wasteful number, since it uses less digits than its factorization.
1002020132019 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 418030994.
The product of its (nonzero) digits is 216, while the sum is 21.
The spelling of 1002020132019 in words is "one trillion, two billion, twenty million, one hundred thirty-two thousand, nineteen".
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