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100212122012001 = 333404040670667
BaseRepresentation
bin10110110010010001110011…
…111011110100100101100001
3111010211012000002022020010120
4112302101303323310211201
5101113333411213341001
6553044451401350453
730052041542404146
oct2662216373644541
9433735002266116
10100212122012001
1129a267a439540a
12b2a5944a98429
1343bbc6897958c
141aa6414bd23cd
15b8bb32066236
hex5b2473ef4961

100212122012001 has 4 divisors (see below), whose sum is σ = 133616162682672. Its totient is φ = 66808081341332.

The previous prime is 100212122011993. The next prime is 100212122012011. The reversal of 100212122012001 is 100210221212001.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 100212122012001 - 23 = 100212122011993 is a prime.

It is not an unprimeable number, because it can be changed into a prime (100212122012011) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16702020335331 + ... + 16702020335336.

It is an arithmetic number, because the mean of its divisors is an integer number (33404040670668).

Almost surely, 2100212122012001 is an apocalyptic number.

It is an amenable number.

100212122012001 is a deficient number, since it is larger than the sum of its proper divisors (33404040670671).

100212122012001 is an equidigital number, since it uses as much as digits as its factorization.

100212122012001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 33404040670670.

The product of its (nonzero) digits is 32, while the sum is 15.

Adding to 100212122012001 its reverse (100210221212001), we get a palindrome (200422343224002).

The spelling of 100212122012001 in words is "one hundred trillion, two hundred twelve billion, one hundred twenty-two million, twelve thousand, one".

Divisors: 1 3 33404040670667 100212122012001