10021431413129 has 4 divisors (see below), whose sum is σ = 10038161683200. Its totient is φ = 10004701143060.

The previous prime is 10021431413117. The next prime is 10021431413159. The reversal of 10021431413129 is 92131413412001.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 10021431413129 - 2⁸ = 10021431412873 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10021431413095 and 10021431413104.

It is not an unprimeable number, because it can be changed into a prime (10021431413159) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8365134137 + ... + 8365135334.

It is an arithmetic number, because the mean of its divisors is an integer number (2509540420800).

Almost surely, 2^{10021431413129} is an apocalyptic number.

It is an amenable number.

10021431413129 is a deficient number, since it is larger than the sum of its proper divisors (16730270071).

10021431413129 is an equidigital number, since it uses as much as digits as its factorization.

10021431413129 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 16730270070.

The product of its (nonzero) digits is 5184, while the sum is 32.

The spelling of 10021431413129 in words is "ten trillion, twenty-one billion, four hundred thirty-one million, four hundred thirteen thousand, one hundred twenty-nine".