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100223122001 = 599167317399
BaseRepresentation
bin101110101010111000…
…0110111101001010001
3100120200201111010002112
41131111300313221101
53120224104401001
6114013013155105
710145423323652
oct1352560675121
9316621433075
10100223122001
1139560380a52
121751062ba95
1395b2b011b2
144bca941529
152918b0ecbb
hex1755c37a51

100223122001 has 4 divisors (see below), whose sum is σ = 100390440000. Its totient is φ = 100055804004.

The previous prime is 100223121991. The next prime is 100223122009. The reversal of 100223122001 is 100221322001.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 100223122001 - 218 = 100222859857 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (100223122009) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 83658101 + ... + 83659298.

It is an arithmetic number, because the mean of its divisors is an integer number (25097610000).

Almost surely, 2100223122001 is an apocalyptic number.

It is an amenable number.

100223122001 is a deficient number, since it is larger than the sum of its proper divisors (167317999).

100223122001 is an equidigital number, since it uses as much as digits as its factorization.

100223122001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 167317998.

The product of its (nonzero) digits is 48, while the sum is 14.

Adding to 100223122001 its reverse (100221322001), we get a palindrome (200444444002).

The spelling of 100223122001 in words is "one hundred billion, two hundred twenty-three million, one hundred twenty-two thousand, one".

Divisors: 1 599 167317399 100223122001