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10023043341 = 33341014447
BaseRepresentation
bin10010101010110101…
…11000000100001101
3221212112010100122110
421111122320010031
5131011344341331
64334324334233
7503244314463
oct112532700415
927775110573
1010023043341
1142838238a3
121b38844379
13c396c7b9c
146b1240833
153d9e10946
hex2556b810d

10023043341 has 4 divisors (see below), whose sum is σ = 13364057792. Its totient is φ = 6682028892.

The previous prime is 10023043319. The next prime is 10023043357. The reversal of 10023043341 is 14334032001.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 10023043341 - 25 = 10023043309 is a prime.

It is a super-2 number, since 2×100230433412 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10023043301) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1670507221 + ... + 1670507226.

It is an arithmetic number, because the mean of its divisors is an integer number (3341014448).

Almost surely, 210023043341 is an apocalyptic number.

It is an amenable number.

10023043341 is a deficient number, since it is larger than the sum of its proper divisors (3341014451).

10023043341 is an equidigital number, since it uses as much as digits as its factorization.

10023043341 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3341014450.

The product of its (nonzero) digits is 864, while the sum is 21.

Adding to 10023043341 its reverse (14334032001), we get a palindrome (24357075342).

The spelling of 10023043341 in words is "ten billion, twenty-three million, forty-three thousand, three hundred forty-one".

Divisors: 1 3 3341014447 10023043341