Base | Representation |
---|---|
bin | 11101001011001011001… |
… | …00001001101010011001 |
3 | 10112211110011110002021102 |
4 | 32211211210021222121 |
5 | 112410434411334140 |
6 | 2044302142521145 |
7 | 132265116635114 |
oct | 16454544115231 |
9 | 3484404402242 |
10 | 1002431355545 |
11 | 357146404344 |
12 | 1423402961b5 |
13 | 736b4c12469 |
14 | 3673730957b |
15 | 1b11ee32e15 |
hex | e965909a99 |
1002431355545 has 16 divisors (see below), whose sum is σ = 1204641677568. Its totient is φ = 800796119040.
The previous prime is 1002431355539. The next prime is 1002431355587. The reversal of 1002431355545 is 5455531342001.
It is not a de Polignac number, because 1002431355545 - 234 = 985251486361 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1002431355499 and 1002431355508.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 22876697 + ... + 22920473.
It is an arithmetic number, because the mean of its divisors is an integer number (75290104848).
Almost surely, 21002431355545 is an apocalyptic number.
It is an amenable number.
1002431355545 is a deficient number, since it is larger than the sum of its proper divisors (202210322023).
1002431355545 is an equidigital number, since it uses as much as digits as its factorization.
1002431355545 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 50240.
The product of its (nonzero) digits is 180000, while the sum is 38.
Adding to 1002431355545 its reverse (5455531342001), we get a palindrome (6457962697546).
The spelling of 1002431355545 in words is "one trillion, two billion, four hundred thirty-one million, three hundred fifty-five thousand, five hundred forty-five".
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