1002443312111 has 4 divisors (see below), whose sum is σ = 1002524225424. Its totient is φ = 1002362398800.

The previous prime is 1002443312063. The next prime is 1002443312141. The reversal of 1002443312111 is 1112133442001.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1002443312111 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1002443312141) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 40438070 + ... + 40462851.

It is an arithmetic number, because the mean of its divisors is an integer number (250631056356).

Almost surely, 2^{1002443312111} is an apocalyptic number.

1002443312111 is a deficient number, since it is larger than the sum of its proper divisors (80913313).

1002443312111 is an equidigital number, since it uses as much as digits as its factorization.

1002443312111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 80913312.

The product of its (nonzero) digits is 576, while the sum is 23.

Adding to 1002443312111 its reverse (1112133442001), we get a palindrome (2114576754112).

The spelling of 1002443312111 in words is "one trillion, two billion, four hundred forty-three million, three hundred twelve thousand, one hundred eleven".