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100302112113 = 374776291053
BaseRepresentation
bin101110101101001111…
…0001100010101110001
3100120220020010020011020
41131122132030111301
53120404320041423
6114024514210053
710150402612560
oct1353236142561
9316806106136
10100302112113
11395a0a22435
1217532b83929
1395c62999c8
144bd7223bd7
152920a144e3
hex175a78c571

100302112113 has 8 divisors (see below), whose sum is σ = 152841313728. Its totient is φ = 57315492624.

The previous prime is 100302112091. The next prime is 100302112117. The reversal of 100302112113 is 311211203001.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 100302112113 - 25 = 100302112081 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 100302112092 and 100302112101.

It is not an unprimeable number, because it can be changed into a prime (100302112117) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2388145506 + ... + 2388145547.

It is an arithmetic number, because the mean of its divisors is an integer number (19105164216).

Almost surely, 2100302112113 is an apocalyptic number.

It is an amenable number.

100302112113 is a deficient number, since it is larger than the sum of its proper divisors (52539201615).

100302112113 is an equidigital number, since it uses as much as digits as its factorization.

100302112113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4776291063.

The product of its (nonzero) digits is 36, while the sum is 15.

Adding to 100302112113 its reverse (311211203001), we get a palindrome (411513315114).

The spelling of 100302112113 in words is "one hundred billion, three hundred two million, one hundred twelve thousand, one hundred thirteen".

Divisors: 1 3 7 21 4776291053 14328873159 33434037371 100302112113