100311243303 has 4 divisors (see below), whose sum is σ = 133748324408. Its totient is φ = 66874162200.

The previous prime is 100311243289. The next prime is 100311243467. The reversal of 100311243303 is 303342113001.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 303342113001 = 3 ⋅101114037667.

It is not a de Polignac number, because 100311243303 - 2⁸ = 100311243047 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 100311243303.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (100311243203) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16718540548 + ... + 16718540553.

It is an arithmetic number, because the mean of its divisors is an integer number (33437081102).

Almost surely, 2^100311243303 is an apocalyptic number.

100311243303 is a deficient number, since it is larger than the sum of its proper divisors (33437081105).

100311243303 is an equidigital number, since it uses as much as digits as its factorization.

100311243303 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 33437081104.

The product of its (nonzero) digits is 648, while the sum is 21.

Adding to 100311243303 its reverse (303342113001), we get a palindrome (403653356304).

The spelling of 100311243303 in words is "one hundred billion, three hundred eleven million, two hundred forty-three thousand, three hundred three".