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1003113000023 = 7183921168353
BaseRepresentation
bin11101001100011100011…
…00011010110001010111
310112220012200002012201012
432212032030122301113
5112413333412000043
62044453532522435
7132321034546601
oct16461614326127
93486180065635
101003113000023
11357466156992
121424b062041b
13737931c5aa4
143679da66171
151b15ebcba18
hexe98e31ac57

1003113000023 has 8 divisors (see below), whose sum is σ = 1017259515936. Its totient is φ = 988966988800.

The previous prime is 1003113000017. The next prime is 1003113000047. The reversal of 1003113000023 is 3200003113001.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1003113000023 - 210 = 1003112998999 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1003112999971 and 1003113000007.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1003113000223) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5874215 + ... + 6042567.

It is an arithmetic number, because the mean of its divisors is an integer number (127157439492).

Almost surely, 21003113000023 is an apocalyptic number.

1003113000023 is a deficient number, since it is larger than the sum of its proper divisors (14146515913).

1003113000023 is an equidigital number, since it uses as much as digits as its factorization.

1003113000023 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 252345.

The product of its (nonzero) digits is 54, while the sum is 14.

Adding to 1003113000023 its reverse (3200003113001), we get a palindrome (4203116113024).

The spelling of 1003113000023 in words is "one trillion, three billion, one hundred thirteen million, twenty-three", and thus it is an aban number.

Divisors: 1 71 83921 168353 5958391 11953063 14128352113 1003113000023