Search a number
-
+
1003113210295 = 5728660377437
BaseRepresentation
bin11101001100011100011…
…01001110000110110111
310112220012200110220011001
432212032031032012313
5112413333440212140
62044453541224131
7132321036413620
oct16461615160667
93486180426131
101003113210295
1135746628a969
121424b0702047
137379326a701
143679dabca47
151b15ec1de9a
hexe98e34e1b7

1003113210295 has 8 divisors (see below), whose sum is σ = 1375698117024. Its totient is φ = 687849058464.

The previous prime is 1003113210289. The next prime is 1003113210313. The reversal of 1003113210295 is 5920123113001.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1003113210295 - 221 = 1003111113143 is a prime.

It is a super-2 number, since 2×10031132102952 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 14330188684 + ... + 14330188753.

It is an arithmetic number, because the mean of its divisors is an integer number (171962264628).

Almost surely, 21003113210295 is an apocalyptic number.

1003113210295 is a deficient number, since it is larger than the sum of its proper divisors (372584906729).

1003113210295 is an equidigital number, since it uses as much as digits as its factorization.

1003113210295 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 28660377449.

The product of its (nonzero) digits is 1620, while the sum is 28.

Adding to 1003113210295 its reverse (5920123113001), we get a palindrome (6923236323296).

The spelling of 1003113210295 in words is "one trillion, three billion, one hundred thirteen million, two hundred ten thousand, two hundred ninety-five".

Divisors: 1 5 7 35 28660377437 143301887185 200622642059 1003113210295