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10031310314 = 25015655157
BaseRepresentation
bin10010101011110100…
…11010010111101010
3221220002200100210122
421111322122113222
5131021003412224
64335221443242
7503404505444
oct112572322752
927802610718
1010031310314
11428845aa03
121b3b570522
13c3b33099c
146b2393494
153da9e515e
hex255e9a5ea

10031310314 has 4 divisors (see below), whose sum is σ = 15046965474. Its totient is φ = 5015655156.

The previous prime is 10031310313. The next prime is 10031310347. The reversal of 10031310314 is 41301313001.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 8983817089 + 1047493225 = 94783^2 + 32365^2 .

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 10031310292 and 10031310301.

It is not an unprimeable number, because it can be changed into a prime (10031310313) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2507827577 + ... + 2507827580.

Almost surely, 210031310314 is an apocalyptic number.

10031310314 is a deficient number, since it is larger than the sum of its proper divisors (5015655160).

10031310314 is an equidigital number, since it uses as much as digits as its factorization.

10031310314 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5015655159.

The product of its (nonzero) digits is 108, while the sum is 17.

Adding to 10031310314 its reverse (41301313001), we get a palindrome (51332623315).

The spelling of 10031310314 in words is "ten billion, thirty-one million, three hundred ten thousand, three hundred fourteen".

Divisors: 1 2 5015655157 10031310314