1003225413433 has 8 divisors (see below), whose sum is σ = 1024847742600. Its totient is φ = 981770052480.

The previous prime is 1003225413413. The next prime is 1003225413439. The reversal of 1003225413433 is 3343145223001.

It is a happy number.

It can be written as a sum of positive squares in 4 ways, for example, as 33557843344 + 969667570089 = 183188^2 + 984717^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1003225413433 - 2¹³ = 1003225405241 is a prime.

It is a super-3 number, since 3×1003225413433³ (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1003225413395 and 1003225413404.

It is not an unprimeable number, because it can be changed into a prime (1003225413439) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 41729908 + ... + 41753941.

It is an arithmetic number, because the mean of its divisors is an integer number (128105967825).

Almost surely, 2^{1003225413433} is an apocalyptic number.

It is an amenable number.

1003225413433 is a deficient number, since it is larger than the sum of its proper divisors (21622329167).

1003225413433 is an equidigital number, since it uses as much as digits as its factorization.

1003225413433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 83484107.

The product of its (nonzero) digits is 25920, while the sum is 31.

The spelling of 1003225413433 in words is "one trillion, three billion, two hundred twenty-five million, four hundred thirteen thousand, four hundred thirty-three".