1003252021 has 4 divisors (see below), whose sum is σ = 1008450412. Its totient is φ = 998053632.

The previous prime is 1003252007. The next prime is 1003252057. The reversal of 1003252021 is 1202523001.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 1202523001 = 14107 ⋅85243.

It can be written as a sum of positive squares in 2 ways, for example, as 722856996 + 280395025 = 26886^2 + 16745^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1003252021 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1003251986 and 1003252004.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1003252321) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2598906 + ... + 2599291.

It is an arithmetic number, because the mean of its divisors is an integer number (252112603).

Almost surely, 2^1003252021 is an apocalyptic number.

It is an amenable number.

1003252021 is a deficient number, since it is larger than the sum of its proper divisors (5198391).

1003252021 is an equidigital number, since it uses as much as digits as its factorization.

1003252021 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5198390.

The product of its (nonzero) digits is 120, while the sum is 16.

The square root of 1003252021 is about 31674.1538324231. The cubic root of 1003252021 is about 1001.0828340472.

Adding to 1003252021 its reverse (1202523001), we get a palindrome (2205775022).

The spelling of 1003252021 in words is "one billion, three million, two hundred fifty-two thousand, twenty-one".