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100330012133 = 137717693241
BaseRepresentation
bin101110101110000100…
…0100111110111100101
3100120222011121200210022
41131130020213313211
53120433440342013
6114031352204525
710151162014001
oct1353410476745
9316864550708
10100330012133
11396057490aa
1217540399745
1395cbcb7bb0
144bdac07701
1529231c6008
hex175c227de5

100330012133 has 4 divisors (see below), whose sum is σ = 108047705388. Its totient is φ = 92612318880.

The previous prime is 100330012121. The next prime is 100330012193. The reversal of 100330012133 is 331210033001.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 331210033001 = 437702558907.

It can be written as a sum of positive squares in 2 ways, for example, as 59791008484 + 40539003649 = 244522^2 + 201343^2 .

It is a cyclic number.

It is not a de Polignac number, because 100330012133 - 28 = 100330011877 is a prime.

It is a super-2 number, since 2×1003300121332 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (100330012193) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3858846608 + ... + 3858846633.

It is an arithmetic number, because the mean of its divisors is an integer number (27011926347).

Almost surely, 2100330012133 is an apocalyptic number.

100330012133 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

100330012133 is a deficient number, since it is larger than the sum of its proper divisors (7717693255).

100330012133 is an equidigital number, since it uses as much as digits as its factorization.

100330012133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7717693254.

The product of its (nonzero) digits is 162, while the sum is 17.

Adding to 100330012133 its reverse (331210033001), we get a palindrome (431540045134).

The spelling of 100330012133 in words is "one hundred billion, three hundred thirty million, twelve thousand, one hundred thirty-three".

Divisors: 1 13 7717693241 100330012133