Base | Representation |
---|---|
bin | 10010101100000001… |
… | …10111101001101001 |
3 | 221220012212100212220 |
4 | 21112000313221221 |
5 | 131021422044423 |
6 | 4335322024253 |
7 | 503425055640 |
oct | 112600675151 |
9 | 27805770786 |
10 | 10033003113 |
11 | 4289406811 |
12 | 1b40048089 |
13 | c3b7a4343 |
14 | 6b26b4357 |
15 | 3dac2b9e3 |
hex | 256037a69 |
10033003113 has 48 divisors (see below), whose sum is σ = 15895047168. Its totient is φ = 5513155200.
The previous prime is 10033003103. The next prime is 10033003117. The reversal of 10033003113 is 31130033001.
It is not a de Polignac number, because 10033003113 - 26 = 10033003049 is a prime.
It is a super-2 number, since 2×100330031132 (a number of 21 digits) contains 22 as substring.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 10033003092 and 10033003101.
It is not an unprimeable number, because it can be changed into a prime (10033003117) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 2504370 + ... + 2508372.
It is an arithmetic number, because the mean of its divisors is an integer number (331146816).
Almost surely, 210033003113 is an apocalyptic number.
It is an amenable number.
10033003113 is a deficient number, since it is larger than the sum of its proper divisors (5862044055).
10033003113 is an equidigital number, since it uses as much as digits as its factorization.
10033003113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4166 (or 4125 counting only the distinct ones).
The product of its (nonzero) digits is 81, while the sum is 15.
Adding to 10033003113 its reverse (31130033001), we get a palindrome (41163036114).
The spelling of 10033003113 in words is "ten billion, thirty-three million, three thousand, one hundred thirteen".
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