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10034303151 = 33344767717
BaseRepresentation
bin10010101100001011…
…10101000010101111
3221220022022102012110
421112011311002233
5131022240200101
64335405535103
7503442112065
oct112605650257
927808272173
1010034303151
11428a114524
121b40574493
13c3bb3acb2
146b2932035
153dadd6cd6
hex2561750af

10034303151 has 4 divisors (see below), whose sum is σ = 13379070872. Its totient is φ = 6689535432.

The previous prime is 10034303077. The next prime is 10034303197. The reversal of 10034303151 is 15130343001.

10034303151 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 10034303151 - 229 = 9497432239 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10034303651) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1672383856 + ... + 1672383861.

It is an arithmetic number, because the mean of its divisors is an integer number (3344767718).

Almost surely, 210034303151 is an apocalyptic number.

10034303151 is a deficient number, since it is larger than the sum of its proper divisors (3344767721).

10034303151 is an equidigital number, since it uses as much as digits as its factorization.

10034303151 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3344767720.

The product of its (nonzero) digits is 540, while the sum is 21.

Adding to 10034303151 its reverse (15130343001), we get a palindrome (25164646152).

The spelling of 10034303151 in words is "ten billion, thirty-four million, three hundred three thousand, one hundred fifty-one".

Divisors: 1 3 3344767717 10034303151