10040121131 has 4 divisors (see below), whose sum is σ = 10040339832. Its totient is φ = 10039902432.

The previous prime is 10040121101. The next prime is 10040121191. The reversal of 10040121131 is 13112104001.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 13112104001 = 56443 ⋅232307.

It is a cyclic number.

It is not a de Polignac number, because 10040121131 - 2⁶ = 10040121067 is a prime.

It is a super-2 number, since 2×10040121131² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (10040121101) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11006 + ... + 142131.

It is an arithmetic number, because the mean of its divisors is an integer number (2510084958).

Almost surely, 2^10040121131 is an apocalyptic number.

10040121131 is a deficient number, since it is larger than the sum of its proper divisors (218701).

10040121131 is an equidigital number, since it uses as much as digits as its factorization.

10040121131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 218700.

The product of its (nonzero) digits is 24, while the sum is 14.

Adding to 10040121131 its reverse (13112104001), we get a palindrome (23152225132).

The spelling of 10040121131 in words is "ten billion, forty million, one hundred twenty-one thousand, one hundred thirty-one".