1004012331433 has 8 divisors (see below), whose sum is σ = 1038859521480. Its totient is φ = 969180213120.

The previous prime is 1004012331401. The next prime is 1004012331451. The reversal of 1004012331433 is 3341332104001.

1004012331433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It can be written as a sum of positive squares in 4 ways, for example, as 29600514304 + 974411817129 = 172048^2 + 987123^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1004012331433 - 2⁵ = 1004012331401 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1004012331398 and 1004012331407.

It is not an unprimeable number, because it can be changed into a prime (1004012331233) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3632308 + ... + 3898933.

It is an arithmetic number, because the mean of its divisors is an integer number (129857440185).

Almost surely, 2^{1004012331433} is an apocalyptic number.

It is an amenable number.

1004012331433 is a deficient number, since it is larger than the sum of its proper divisors (34847190047).

1004012331433 is an equidigital number, since it uses as much as digits as its factorization.

1004012331433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7535867.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 1004012331433 its reverse (3341332104001), we get a palindrome (4345344435434).

The spelling of 1004012331433 in words is "one trillion, four billion, twelve million, three hundred thirty-one thousand, four hundred thirty-three".