10040151311 has 4 divisors (see below), whose sum is σ = 10041158712. Its totient is φ = 10039143912.

The previous prime is 10040151307. The next prime is 10040151347. The reversal of 10040151311 is 11315104001.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 10040151311 - 2² = 10040151307 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 10040151311.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10040153311) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 488600 + ... + 508733.

It is an arithmetic number, because the mean of its divisors is an integer number (2510289678).

Almost surely, 2^10040151311 is an apocalyptic number.

10040151311 is a deficient number, since it is larger than the sum of its proper divisors (1007401).

10040151311 is an equidigital number, since it uses as much as digits as its factorization.

10040151311 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1007400.

The product of its (nonzero) digits is 60, while the sum is 17.

Adding to 10040151311 its reverse (11315104001), we get a palindrome (21355255312).

The spelling of 10040151311 in words is "ten billion, forty million, one hundred fifty-one thousand, three hundred eleven".