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100403000023 = 167601215569
BaseRepresentation
bin101110110000001111…
…1000011001011010111
3100121011020221212100111
41131200133003023113
53121111132000043
6114042520423451
710153036263454
oct1354037031327
9317136855314
10100403000023
113964296aa77
1217560917b87
1396111616b1
144c067a682b
1529297e209d
hex17607c32d7

100403000023 has 4 divisors (see below), whose sum is σ = 101004215760. Its totient is φ = 99801784288.

The previous prime is 100402999997. The next prime is 100403000053. The reversal of 100403000023 is 320000304001.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-100403000023 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 100402999967 and 100403000012.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (100403000053) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 300607618 + ... + 300607951.

It is an arithmetic number, because the mean of its divisors is an integer number (25251053940).

Almost surely, 2100403000023 is an apocalyptic number.

100403000023 is a deficient number, since it is larger than the sum of its proper divisors (601215737).

100403000023 is an equidigital number, since it uses as much as digits as its factorization.

100403000023 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 601215736.

The product of its (nonzero) digits is 72, while the sum is 13.

Adding to 100403000023 its reverse (320000304001), we get a palindrome (420403304024).

The spelling of 100403000023 in words is "one hundred billion, four hundred three million, twenty-three", and thus it is an aban number.

Divisors: 1 167 601215569 100403000023