100404123211033 has 4 divisors (see below), whose sum is σ = 102105888011280. Its totient is φ = 98702358410788.

The previous prime is 100404123210997. The next prime is 100404123211199. The reversal of 100404123211033 is 330112321404001.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 100404123211033 - 2⁴¹ = 98205099955481 is a prime.

It is a super-3 number, since 3×100404123211033³ (a number of 43 digits) contains 333 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 100404123210989 and 100404123211007.

It is not an unprimeable number, because it can be changed into a prime (100404123211933) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 850882400035 + ... + 850882400152.

It is an arithmetic number, because the mean of its divisors is an integer number (25526472002820).

Almost surely, 2^{100404123211033} is an apocalyptic number.

It is an amenable number.

100404123211033 is a deficient number, since it is larger than the sum of its proper divisors (1701764800247).

100404123211033 is an equidigital number, since it uses as much as digits as its factorization.

100404123211033 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1701764800246.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 100404123211033 its reverse (330112321404001), we get a palindrome (430516444615034).

The spelling of 100404123211033 in words is "one hundred trillion, four hundred four billion, one hundred twenty-three million, two hundred eleven thousand, thirty-three".