100405363133 has 4 divisors (see below), whose sum is σ = 104770813728. Its totient is φ = 96039912540.

The previous prime is 100405363081. The next prime is 100405363139. The reversal of 100405363133 is 331363504001.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 100405363133 - 2¹² = 100405359037 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 100405363096 and 100405363105.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (100405363139) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2182725263 + ... + 2182725308.

It is an arithmetic number, because the mean of its divisors is an integer number (26192703432).

Almost surely, 2^100405363133 is an apocalyptic number.

It is an amenable number.

100405363133 is a deficient number, since it is larger than the sum of its proper divisors (4365450595).

100405363133 is an equidigital number, since it uses as much as digits as its factorization.

100405363133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4365450594.

The product of its (nonzero) digits is 9720, while the sum is 29.

Adding to 100405363133 its reverse (331363504001), we get a palindrome (431768867134).

The spelling of 100405363133 in words is "one hundred billion, four hundred five million, three hundred sixty-three thousand, one hundred thirty-three".