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100406153131 = 4313031792039
BaseRepresentation
bin101110110000010101…
…1000100111110101011
3100121011110220001121021
41131200223010332223
53121112433400011
6114043112153311
710153105135264
oct1354053047653
9317143801537
10100406153131
1139644723a49
1217561998837
1396119c693b
144c06d8796b
152929c16471
hex1760ac4fab

100406153131 has 8 divisors (see below), whose sum is σ = 102820087040. Its totient is φ = 97995805992.

The previous prime is 100406153119. The next prime is 100406153161. The reversal of 100406153131 is 131351604001.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 100406153131 - 215 = 100406120363 is a prime.

It is a super-2 number, since 2×1004061531312 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 100406153096 and 100406153105.

It is not an unprimeable number, because it can be changed into a prime (100406153101) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 839991 + ... + 952048.

It is an arithmetic number, because the mean of its divisors is an integer number (12852510880).

Almost surely, 2100406153131 is an apocalyptic number.

100406153131 is a deficient number, since it is larger than the sum of its proper divisors (2413933909).

100406153131 is a wasteful number, since it uses less digits than its factorization.

100406153131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1793385.

The product of its (nonzero) digits is 1080, while the sum is 25.

Adding to 100406153131 its reverse (131351604001), we get a palindrome (231757757132).

The spelling of 100406153131 in words is "one hundred billion, four hundred six million, one hundred fifty-three thousand, one hundred thirty-one".

Divisors: 1 43 1303 56029 1792039 77057677 2335026817 100406153131