10041100112113 has 4 divisors (see below), whose sum is σ = 11475542985280. Its totient is φ = 8606657238948.

The previous prime is 10041100112089. The next prime is 10041100112201. The reversal of 10041100112113 is 31121100114001.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 10041100112113 - 2¹⁷ = 10041099981041 is a prime.

It is a super-2 number, since 2×10041100112113² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (10041100112713) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 717221436573 + ... + 717221436586.

It is an arithmetic number, because the mean of its divisors is an integer number (2868885746320).

Almost surely, 2^{10041100112113} is an apocalyptic number.

It is an amenable number.

10041100112113 is a deficient number, since it is larger than the sum of its proper divisors (1434442873167).

10041100112113 is an equidigital number, since it uses as much as digits as its factorization.

10041100112113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1434442873166.

The product of its (nonzero) digits is 24, while the sum is 16.

Adding to 10041100112113 its reverse (31121100114001), we get a palindrome (41162200226114).

The spelling of 10041100112113 in words is "ten trillion, forty-one billion, one hundred million, one hundred twelve thousand, one hundred thirteen".