10041121 has 4 divisors (see below), whose sum is σ = 10047744. Its totient is φ = 10034500.

The previous prime is 10041113. The next prime is 10041131. The reversal of 10041121 is 12114001.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 10041121 - 2³ = 10041113 is a prime.

It is a super-2 number, since 2×10041121² = 201648221873282, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10041098 and 10041107.

It is not an unprimeable number, because it can be changed into a prime (10041131) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 216 + ... + 4486.

It is an arithmetic number, because the mean of its divisors is an integer number (2511936).

Almost surely, 2^10041121 is an apocalyptic number.

It is an amenable number.

10041121 is a deficient number, since it is larger than the sum of its proper divisors (6623).

10041121 is an equidigital number, since it uses as much as digits as its factorization.

10041121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6622.

The product of its (nonzero) digits is 8, while the sum is 10.

The square root of 10041121 is about 3168.7727908451. The cubic root of 10041121 is about 215.7383735092.

Adding to 10041121 its reverse (12114001), we get a palindrome (22155122).

The spelling of 10041121 in words is "ten million, forty-one thousand, one hundred twenty-one".