Base | Representation |
---|---|
bin | 10010101100111111… |
… | …10101110101100111 |
3 | 221220210010212010000 |
4 | 21112133311311213 |
5 | 131031011402101 |
6 | 4340212032343 |
7 | 503554062414 |
oct | 112637656547 |
9 | 27823125100 |
10 | 10041122151 |
11 | 4292a51765 |
12 | 1b429026b3 |
13 | c403879c8 |
14 | 6b37c910b |
15 | 3db7d2486 |
hex | 2567f5d67 |
10041122151 has 40 divisors (see below), whose sum is σ = 15205245264. Its totient is φ = 6602860800.
The previous prime is 10041122137. The next prime is 10041122191. The reversal of 10041122151 is 15122114001.
10041122151 is a `hidden beast` number, since 100 + 411 + 2 + 2 + 151 = 666.
It is not a de Polignac number, because 10041122151 - 213 = 10041113959 is a prime.
It is a super-3 number, since 3×100411221513 (a number of 31 digits) contains 333 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (10041122101) by changing a digit.
It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 2313055 + ... + 2317391.
Almost surely, 210041122151 is an apocalyptic number.
10041122151 is a deficient number, since it is larger than the sum of its proper divisors (5164123113).
10041122151 is a wasteful number, since it uses less digits than its factorization.
10041122151 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4733 (or 4724 counting only the distinct ones).
The product of its (nonzero) digits is 80, while the sum is 18.
Adding to 10041122151 its reverse (15122114001), we get a palindrome (25163236152).
The spelling of 10041122151 in words is "ten billion, forty-one million, one hundred twenty-two thousand, one hundred fifty-one".
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