100411351441 has 4 divisors (see below), whose sum is σ = 100412224000. Its totient is φ = 100410478884.

The previous prime is 100411351427. The next prime is 100411351457. The reversal of 100411351441 is 144153114001.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 144153114001 = 13 ⋅11088701077.

It is a cyclic number.

It is not a de Polignac number, because 100411351441 - 2⁹ = 100411350929 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (100411351421) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 231681 + ... + 504478.

It is an arithmetic number, because the mean of its divisors is an integer number (25103056000).

Almost surely, 2^100411351441 is an apocalyptic number.

It is an amenable number.

100411351441 is a deficient number, since it is larger than the sum of its proper divisors (872559).

100411351441 is an equidigital number, since it uses as much as digits as its factorization.

100411351441 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 872558.

The product of its (nonzero) digits is 960, while the sum is 25.

Adding to 100411351441 its reverse (144153114001), we get a palindrome (244564465442).

The spelling of 100411351441 in words is "one hundred billion, four hundred eleven million, three hundred fifty-one thousand, four hundred forty-one".