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10041312523 = 115323171491
BaseRepresentation
bin10010101101000001…
…00100010100001011
3221220210111112020211
421112200210110023
5131031034000043
64340220101551
7503555514424
oct112640442413
927823445224
1010041312523
1142930717a0
121b429948b7
13c40423558
146b383864b
153db81da9d
hex25682450b

10041312523 has 8 divisors (see below), whose sum is σ = 10956280896. Its totient is φ = 9126697800.

The previous prime is 10041312521. The next prime is 10041312559. The reversal of 10041312523 is 32521314001.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 10041312523 - 21 = 10041312521 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 10041312494 and 10041312503.

It is not an unprimeable number, because it can be changed into a prime (10041312521) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 27193 + ... + 144298.

It is an arithmetic number, because the mean of its divisors is an integer number (1369535112).

Almost surely, 210041312523 is an apocalyptic number.

10041312523 is a deficient number, since it is larger than the sum of its proper divisors (914968373).

10041312523 is a wasteful number, since it uses less digits than its factorization.

10041312523 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 176825.

The product of its (nonzero) digits is 720, while the sum is 22.

Adding to 10041312523 its reverse (32521314001), we get a palindrome (42562626524).

The spelling of 10041312523 in words is "ten billion, forty-one million, three hundred twelve thousand, five hundred twenty-three".

Divisors: 1 11 5323 58553 171491 1886401 912846593 10041312523